CH1 Handout Review_page_6

CH1 Handout Review | page 6 | https://thedailydialectics.com/pdfs/education/calculus/calculus-2-2413-HCC/CH1 Handout Review/CH1 Handout Review.pdf

lim x3 -27 _ 33-27 _0 x73 4x-12 4(3)-12 0 x3 -27 _ (x - 3)(x2 +3x +9) _ x24+3x+9 14) 4x -12 A(x - 3) 4 So, lim x3 -27 _ lim x2+3x+9 _ (3)2 +3(3)+9 _ 27 "x93 4x-12 x33 4 4 4 15) lim 2x4-2 _ 2()4-2_0 x>1 3x-3 3()-3 0 2x4 -2 — 2(x4-1) _ 2x2 -1)(x2 +1) _ 2x -1)(x + (x2 + 1) 3x-3 3(x-1) 3(x - 1) 3(x -…